0580/43 Oct/Nov 2022, Question 2: The Quadratic Formula and Completing the Square
Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 19 marks
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The question, in short
Simplify index expressions, work with nth-term formulas, solve a linear equation and a quadratic using the formula, giving answers to 2 decimal places.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (ai) · 1 mark
Simplify the product of two powers of p by adding indices.
- 1p³ × p¹¹ = p³⁺¹¹ = p¹⁴
Answerp¹⁴
Part (aii) · 2 marks
Simplify a quotient of terms in m by dividing coefficients and subtracting indices.
- 118 ÷ 3 = 6, m⁶ ÷ m² = m⁴
- 2= 6m⁴
Answer6m⁴
Part (aiii) · 3 marks
Simplify a fractional power expression raised to −1/3, applying index laws to 27, 64, x⁹ and y²⁷.
- 1= (64/(27x⁹y²⁷))^(1/3)
- 2∛64 = 4, ∛27 = 3, ∛(x⁹) = x³, ∛(y²⁷) = y⁹
- 3= 4/(3x³y⁹)
Answer4/(3x³y⁹) or (4x⁻³y⁻⁹)/3
Part (b) · 2 marks
Use the nth term 3n² to write the first three terms of the sequence.
- 13 × 1² = 3, 3 × 2² = 12, 3 × 3² = 27
- 23, 12, 27
Answer3, 12, 27
Part (ci) · 2 marks
Find the nth term of the linear sequence 13, 16, 19, 22, 25.
- 1Common difference 3, so 3n + k
- 2First term: 3 × 1 + k = 13, k = 10
- 3nth term = 3n + 10
Answer3n + 10
Part (cii) · 2 marks
Find the nth term of the sequence 3, 17, 55, 129, 251.
- 1Differences 14, 38, 74, 122 → 24, 36, 48 → 12, 12: cubic with 12 ÷ 6 = 2, so 2n³
- 2Sequence − 2n³: 3 − 2 = 1, 17 − 16 = 1, 55 − 54 = 1
- 3nth term = 2n³ + 1
Answer2n³ + 1
Part (d) · 3 marks
Solve the equation (3x − 22)/4 = 23 for x.
- 13x − 22 = 4 × 23 = 92
- 23x = 114
- 3x = 38
Answer38
Part (e) · 4 marks
Use the quadratic formula on 3x² + 8x − 20 = 0, showing working and rounding answers to 2 decimal places.
- 1x = (−8 ± √(8² − 4 × 3 × (−20)))/(2 × 3)
- 2= (−8 ± √304)/6
- 3x = (−8 + 17.435…)/6 = 1.572… or x = (−8 − 17.435…)/6 = −4.239…
- 4x = −4.24, 1.57
Answer−4.24, 1.57
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Also searched as: 0580/43/O/N/22 · 0580_w22_qp_43 · 0580 w22 43 · question 2.
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