0580/42 Oct/Nov 2023, Question 11: Composite Functions
Cambridge IGCSE Mathematics 0580 · Paper 42 (Extended) · Calculator · 14 marks
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The question, in short
Use three given functions to evaluate, compose, invert and combine them, and to solve for unknown coefficients and an index.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Evaluate the squared function g at input 3.
- 1g(3) = (3 − 1)² = 4
Answer4
Part (b) · 2 marks
Substitute x − 2 into the linear function f and simplify the result.
- 1f(x − 2) = 1 − 3(x − 2) = 1 − 3x + 6
- 2= 7 − 3x
Answer7 − 3x
Part (c) · 2 marks
Determine the inverse function of the linear function f.
- 1Write y = 1 − 3x, then swap x and y: x = 1 − 3y
- 2Rearrange: 3y = 1 − x
- 3Divide by 3: f⁻¹(x) = (1 − x)/3
Answer(1 − x)/3
Part (d) · 5 marks
Expand the difference of two composite products and match coefficients to find a, b, c.
- 1gf(x) = (1 − 3x − 1)² = 9x²
- 2g(x)f(x) = (x² − 2x + 1)(1 − 3x) = −3x³ + 7x² − 5x + 1
- 3gf(x) − g(x)f(x) = 9x² + 3x³ − 7x² + 5x − 1 = 3x³ + 2x² + 5x − 1
- 4a = 2, b = 5, c = −1
Answera = 2, b = 5, c = −1
Part (e) · 3 marks
Subtract the linear function from the reciprocal function, giving one simplified fraction.
- 13/x − (1 − 3x) = (3 − x(1 − 3x))/x
- 2= (3 − x + 3x²)/x
Answer(3 − x + 3x²)/x
Part (f) · 1 mark
Substitute xⁿ into the reciprocal function and equate exponents to find n.
- 13/xⁿ = 3x⁻ⁿ = 3x⁷
- 2−n = 7, n = −7
Answer−7
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