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0580/43 Oct/Nov 2023, Question 1: Currency Conversions

Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 12 marks

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The question, in short

Using an exchange-rate table for $100, convert money between currencies, split a euro amount in a ratio, and find a lower-bound flight time.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (a) · 2 marks

Change $250 into Indian rupees using the table rate, giving the result to the nearest rupee.

  1. 17437.05 × 250 ÷ 100 = 18 592.625
  2. 2≈ 18 593 rupees

Answer18593

Part (b) · 2 marks

Convert 5400 Chinese yuan into dollars using the table rate, correct to the nearest cent.

  1. 15400 ÷ 671.20 × 100 = 804.529…
  2. 2≈ $804.53

Answer804.53

Part (ci) · 2 marks

Split 3500 euros between travel and hotels in the ratio 4 : 3, finding the travel amount in euros.

  1. 13500 ÷ (4 + 3) = 500
  2. 2Travel = 4 × 500 = 2000 euros

Answer2000

Part (cii) · 3 marks

Find the hotel share in euros, then convert it to pounds using the table rate.

  1. 1Hotels = 3500 − 2000 = 1500 euros
  2. 21500 ÷ 85.35 × 77.05 = 1354.13… pounds

Answer1354.13…

Part (ciii) · 3 marks

With distance 2200 km and speed 740 km/h each rounded, find the lower-bound time in hours and minutes.

  1. 1Lower bound of distance = 2200 − 50 = 2150 km
  2. 2Upper bound of speed = 740 + 10 = 750 km/h
  3. 3Lower bound of time = 2150 ÷ 750 = 2.8666… h
  4. 40.8666… × 60 = 52 minutes, so time = 2 h 52 min

Answer2 h 52 min

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Also searched as: 0580/43/O/N/23 · 0580_w23_qp_43 · 0580 w23 43 · question 1.
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