0580/13 Oct/Nov 2025, Question 21: The nth Term of a Linear Sequence
Cambridge IGCSE Mathematics 0580 · Paper 13 (Core) · Non-calculator · 6 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Sequence starts −6, 1, 8, 15. Find the next term, the term-to-term rule, the nth term, and decide whether 688 belongs to the sequence with reasoning.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Write down the term that follows 15 in the sequence.
- 1Differences: 1 − (−6) = 7, 8 − 1 = 7, 15 − 8 = 7
- 2Next term = 15 + 7 = 22
Answer22
Part (b) · 1 mark
State the rule linking each term to the one before it.
- 1Each term is 7 more than the one before: add 7
AnswerAdd 7
Part (ci) · 2 marks
Find an expression for the nth term of the sequence.
- 1Common difference 7, so nth term = 7n + c
- 2n = 1: 7 + c = −6, so c = −13
- 3nth term = 7n − 13
Answer7n − 13
Part (cii) · 2 marks
Decide whether 688 is in the sequence and explain your reasoning.
- 17n − 13 = 688
- 27n = 701
- 3n = 701 ÷ 7 = 100.14…, not a whole number
- 4No, 688 is not a term because 701 is not divisible by 7
AnswerNo, 7n − 13 = 688 gives 7n = 701 and 701 is not divisible by 7
Stuck on a step? Read the free lesson: The nth Term of a Linear Sequence
Practise more the nth term of a linear sequence questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on the nth term of a linear sequence
Also searched as: 0580/13/O/N/25 · 0580_w25_qp_13 · 0580 w25 13 · question 21.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.