0580/23 Oct/Nov 2025, Question 8: Magnitude of a Vector
Cambridge IGCSE Mathematics 0580 · Paper 23 (Extended) · Non-calculator · 5 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Vector DE is given as the column vector (3, −4). Find a scalar multiple, the magnitude, and the coordinates of E given D is (−2, −3).
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Calculate the column vector 5→DE.
- 15 × (3, −4) = (15, −20)
Answercolumn vector (15, −20)
Part (b) · 2 marks
Work out the magnitude of the vector →DE.
- 1|DE| = √(3² + (−4)²) = √(9 + 16) = √25
- 2= 5
Answer5
Part (c) · 2 marks
Using D at (−2, −3), determine the coordinates of point E.
- 1To get from D to E, add →DE = (3, −4) to D.
- 2x: −2 + 3 = 1 y: −3 + (−4) = −7
- 3E = (1, −7)
Answer(1, −7)
Stuck on a step? Read the free lesson: Magnitude of a Vector
Practise more magnitude of a vector questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on magnitude of a vector
Also searched as: 0580/23/O/N/25 · 0580_w25_qp_23 · 0580 w25 23 · question 8.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.