0580/23 May/Jun 2025, Question 12: Magnitude of a Vector
Cambridge IGCSE Mathematics 0580 · Paper 23 (Extended) · Non-calculator · 5 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Vector questions: multiply a column vector by 5, and find the length of vector JK given points H, K and vector HJ.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 1 mark
Find 5v where v is the column vector (2, −3).
- 15v = column vector (5 × 2, 5 × (−3)) = column vector (10, −15)
Answercolumn vector (10, −15)
Part (b) · 4 marks
Given H(−3, 8), K(−4, 0) and HJ→ = (7, −2), find the magnitude |JK→|.
- 1J = (−3 + 7, 8 − 2) = (4, 6)
- 2→JK = column vector (−4 − 4, 0 − 6) = column vector (−8, −6)
- 3|→JK| = √((−8)² + (−6)²) = √(64 + 36) = √100
- 4= 10
Answer10
Stuck on a step? Read the free lesson: Magnitude of a Vector
Practise more magnitude of a vector questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on magnitude of a vector
Also searched as: 0580/23/M/J/25 · 0580_s25_qp_23 · 0580 s25 23 · question 12.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.