0606/12 Feb/Mar 2026, Question 10: Solving Exponential and Log Equations
Cambridge IGCSE Additional Mathematics 0606 · Paper 12 (Non-calculator) · Non-calculator · 10 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Solve two logarithmic and exponential equations: one involving log base 5 and log base x, and one with powers of 2 and 8, finding the values of x.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 6 marks
Solve log₅(x²) − log₅ x − 3 log_x 5 = 2 for x.
- 1log₅(x²) − log₅ x = 2log₅ x − log₅ x = log₅ x
- 2Change of base: log_x 5 = 1/log₅ x
- 3Let u = log₅ x: u − 3/u = 2, so u² − 2u − 3 = 0
- 4(u − 3)(u + 1) = 0, u = 3 or u = −1
- 5x = 5³ = 125 or x = 5⁻¹ = 1/5
Answerx = 125, x = 1/5
Part (b) · 4 marks
Solve 2 × 8^(2x+1) − 3 × 2^(3x+4) − 64 = 0 for x.
- 18^(2x+1) = 8 × (2^(3x))² and 2^(3x+4) = 16 × 2^(3x)
- 216(2^(3x))² − 48 × 2^(3x) − 64 = 0
- 3Let u = 2^(3x): u² − 3u − 4 = 0, so (u − 4)(u + 1) = 0
- 42^(3x) = 4 (2^(3x) = −1 has no solution)
- 53x = 2, x = 2/3
Answerx = 2/3
Stuck on a step? Read the free lesson: Solving Exponential and Log Equations
Practise more solving exponential and log equations questions
Real 0606 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on solving exponential and log equations
Also searched as: 0606/12/F/M/26 · 0606_m26_qp_12 · 0606 m26 12 · question 10.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.