0606/12 Feb/Mar 2026, Question 9: Unit Vectors and i, j Components
Cambridge IGCSE Additional Mathematics 0606 · Paper 12 (Non-calculator) · Non-calculator · 10 marks
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The question, in short
Using vectors for two moving particles and a point on a line, find positions, test for collision, and determine integer coordinates at a set distance.
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Part (ai) · 1 mark
Give B's position vector as a function of t, starting from (−3, 4) with velocity (4, −2).
- 1Position = start + t × velocity
- 2r_B = (−3, 4) + t(4, −2) = (−3 + 4t, 4 − 2t)
Answercolumn vector (−3, 4) + t × column vector (4, −2), i.e. column vector (−3 + 4t, 4 − 2t)
Part (aii) · 4 marks
Decide whether A and B ever occupy the same point, showing your reasoning.
- 1Position of A: t(2, 1) = (2t, t)
- 2Collide if (2t, t) = (−3 + 4t, 4 − 2t) for the same t
- 3x: 2t = −3 + 4t gives t = 3/2
- 4y: t = 4 − 2t gives t = 4/3
- 5The values of t differ, so the particles do not collide
AnswerThe particles do not collide: equating components gives t = 3/2 and t = 4/3, which are inconsistent
Part (b) · 5 marks
With Q at 3i + 2j and R at −i + 4j, find integer a and b so S = ai + bj lies on line QR and RS has length √5.
- 1QR = (−i + 4j) − (3i + 2j) = −4i + 2j
- 2|QR| = √(16 + 4) = 2√5, so |RS| is half of |QR|
- 3RS = ±(1/2)QR = ±(−2i + j)
- 4OS = OR + RS: (−1 − 2)i + (4 + 1)j = −3i + 5j, or (−1 + 2)i + (4 − 1)j = i + 3j
- 5a = 1, b = 3 or a = −3, b = 5
Answera = 1, b = 3 or a = −3, b = 5
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