0606/12 May/Jun 2026, Question 6: Radians, Arcs and Sectors
Cambridge IGCSE Additional Mathematics 0606 · Paper 12 (Non-calculator) · Non-calculator · 8 marks
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The question, in short
Circle centre O radius r, points A, B, C on circumference, angle AOB = α radians, shaded minor sector AOB. Find α from a perimeter condition, then find r from a given sector area.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 4 marks
Shaded sector perimeter equals major arc ACB length. Find the exact value of α.
- 1Perimeter of shaded sector = 2r + rα
- 2Major arc ACB = r(2π − α)
- 32r + rα = 2πr − rα
- 42α = 2π − 2
- 5α = π − 1
Answerα = π − 1
Part (b) · 4 marks
Shaded sector area is 18(π² − 1). Find the exact value of r, simplified.
- 1(1/2)r²(π − 1) = 18(π² − 1)
- 2r² = 36(π² − 1)/(π − 1)
- 3π² − 1 = (π − 1)(π + 1), so r² = 36(π + 1)
- 4r = 6√(π + 1)
Answerr = 6√(π + 1)
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Also searched as: 0606/12/M/J/26 · 0606_s26_qp_12 · 0606 s26 12 · question 6.
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