Lemmara logoLemmaraWorked solution

0606/12 Oct/Nov 2025, Question 6: Modulus Equations and Inequalities

Cambridge IGCSE Additional Mathematics 0606 · Paper 12 (Non-calculator) · Non-calculator · 5 marks

اقرأ هذا الحل مشروحاً بالعربي ←

The question, in short

Find the values of x satisfying the modulus equation |2x² + x − 10| = 5.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Solution · 5 marks

  1. 12x² + x − 10 = 5 ⇒ 2x² + x − 15 = 0
  2. 2(2x − 5)(x + 3) = 0 ⇒ x = 5/2 or −3
  3. 32x² + x − 10 = −5 ⇒ 2x² + x − 5 = 0
  4. 4x = (−1 ± √(1 + 40))/4 = (−1 ± √41)/4

Answerx = 5/2, x = −3, x = (−1 ± √41)/4

Stuck on a step? Read the free lesson: Modulus Equations and Inequalities

Practise more modulus equations and inequalities questions

Real 0606 past-paper questions, marked on your working like the exam, with a worked solution for every part.

Practise free on Lemmara

More past-paper questions on modulus equations and inequalities

Also searched as: 0606/12/O/N/25 · 0606_w25_qp_12 · 0606 w25 12 · question 6.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.