0606/21 Oct/Nov 2025, Question 2: Modulus Equations and Inequalities
Cambridge IGCSE Additional Mathematics 0606 · Paper 21 (Calculator) · Calculator · 3 marks
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The question, in short
The graph of y = |3x + 3| is shown on a grid from x = −4 to 4 and y = −6 to 6. Use a graphical method to solve |3x + 3| ≥ |x − 2|.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Solution · 3 marks
- 1Draw y = |x − 2|: a V-shape with vertex (2, 0), y-intercept 2
- 2The graphs cross where 3x + 3 = −(x − 2), giving x = −0.25
- 3and where −(3x + 3) = −(x − 2), giving x = −2.5
- 4|3x + 3| is on or above |x − 2| outside these points
- 5x ≤ −2.5 or x ≥ −0.25
Answerx ≤ −2.5, x ≥ −0.25 (with a correct graph of y = |x − 2| drawn)
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Also searched as: 0606/21/O/N/25 · 0606_w25_qp_21 · 0606 w25 21 · question 2.
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