4024/21 May/Jun 2024, Question 2: Estimating the Mean for Grouped Data
Cambridge O Level Mathematics 4024 · Paper 21 (Calculator) · Calculator · 9 marks
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The question, in short
Using a table of midday temperatures at ten mountain heights, complete and interpret a scatter diagram, then estimate a mean time and a histogram bar height from grouped data for 80 adults.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Plot the remaining five height and temperature pairs from the table onto the given scatter diagram.
- 1Plot (100, 3.5), (1250, −4.6), (1450, −6.4), (1125, −4.0) and (1350, −3.8)
AnswerComplete scatter diagram
Part (aii) · 1 mark
State what kind of correlation the plotted points show.
- 1As height increases, temperature decreases: negative correlation
AnswerNegative
Part (aiii) · 1 mark
Add a line of best fit to the scatter diagram.
- 1Rule a straight line through the middle of the points, sloping down, with about as many points above as below
- 2It should pass near the mean point (832.5, −1.38)
AnswerRuled line of best fit
Part (aiv) · 1 mark
Using your line of best fit, estimate the temperature at a height of 1000 m.
- 1Go up from 1000 m to your line, then across to the temperature axis
- 2A good line gives about −2.5 °C (your value depends on your line)
Answer−2.6 (accept −3.1 to −2.1)
Part (bi) · 3 marks
From the grouped frequency table of 80 adults' climb times, work out an estimated mean time.
- 1Midpoints: 6, 7, 7.75, 8.25, 9.5
- 2Σfx = 6×8 + 7×15 + 7.75×20 + 8.25×23 + 9.5×14 = 48 + 105 + 155 + 189.75 + 133 = 630.75
- 3Mean = 630.75 ÷ 80 = 7.884… ≈ 7.88 hours
Answer7.88 or 7.884…
Part (bii) · 1 mark
Given the 5.5 < h ≤ 6.5 bar is 8 mm tall, find the height of the bar for 8 < h ≤ 8.5.
- 15.5 < h ≤ 6.5: frequency density = 8 ÷ 1 = 8, shown by 8 mm, so 1 mm per unit
- 28 < h ≤ 8.5: frequency density = 23 ÷ 0.5 = 46
- 3Height = 46 mm
Answer46
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