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4MA1/1F Jan 2019, Question 14: Percentage Increases and Decreases

Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1F (Foundation) · Calculator · 6 marks

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The question, in short

Using a table of gold prices in dollars per ounce for 1st February 2016 (1126.50) and 1st March 2016 (1236.50), find a percentage rise and a later price after a 19% rise.

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Part (a) · 3 marks

Calculate the percentage increase from 1126.50 to 1236.50 dollars, giving the result to 3 significant figures.

  1. 1Increase = 1236.50 − 1126.50 = 110
  2. 2Percentage increase = 110 ÷ 1126.50 × 100 = 9.7647…
  3. 3= 9.76 (3 s.f.)

Answer9.76

Part (b) · 3 marks

Starting from 1126.50 dollars, apply a 19% rise to get the 1st July 2016 price, rounded to the nearest dollar.

  1. 1A 19% increase means multiply by 1 + 0.19 = 1.19.
  2. 21126.50 × 1.19 = 1340.535
  3. 3To the nearest dollar: 1341

Answer1341

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