4MA1/2H Jan 2023, Question 9: Index Laws with Letters
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 2H (Higher) · Calculator · 7 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Answer four short algebra questions: evaluate a zero power, simplify a cubed product, factorise an expression fully, and find the equation of a straight line from a grid diagram.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 1 mark
State the value of (m + 2)⁰ for a positive integer m.
- 1Any number to the power of 0 is 1, so (m + 2)⁰ = 1
Answer1
Part (b) · 2 marks
Simplify (3a²b⁴)³.
- 1Cube each part: 3³ = 27, (a²)³ = a⁶, (b⁴)³ = b¹²
- 2(3a²b⁴)³ = 27a⁶b¹²
Answer27a⁶b¹²
Part (c) · 2 marks
Factorise 14x²y⁴ + 21x³y² completely.
- 1HCF of the two terms is 7x²y²
- 214x²y⁴ ÷ 7x²y² = 2y² and 21x³y² ÷ 7x²y² = 3x
- 314x²y⁴ + 21x³y² = 7x²y²(2y² + 3x)
Answer7x²y²(2y² + 3x)
Part (d) · 2 marks
Using the grid diagram, write down an equation for the straight line shown.
- 1The line crosses the y-axis at 4, so y-intercept is 4
- 2Gradient = rise/run = (0 − 4)/(2 − 0) = −4/2 = −2
- 3So equation is y = −2x + 4
Answery = −2x + 4
Stuck on a step? Read the free lesson: Index Laws with Letters
Practise more index laws with letters questions
Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on index laws with letters
Also searched as: 4MA1 2H January 2023 · 4MA1/2H · 4ma1 jan23 2h · question 9.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.