4MA1/2F Jun 2018, Question 24: Laws of Indices
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 2F (Foundation) · Calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Use index laws to find the unknown exponent in two equations involving powers of 2 and 13.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 2 marks
Find n where 8 divided by 2⁷ equals 2ⁿ.
- 18 = 2³, so the fraction is 2³ ÷ 2⁷
- 2Dividing powers subtracts them: 2^(3 − 7) = 2^(−4)
- 3So n = −4
Answer−4
Part (b) · 2 marks
Find k where (13⁻⁶)⁴ multiplied by 13⁵ equals 13ᵏ.
- 1(13⁻⁶)⁴ = 13^(−6 × 4) = 13⁻²⁴
- 213⁻²⁴ × 13⁵ = 13^(−24 + 5)
- 3−24 + 5 = −19, so k = −19
Answer−19
Stuck on a step? Read the free lesson: Laws of Indices
Practise more laws of indices questions
Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on laws of indices
Also searched as: 4MA1 2F June 2018 · 4MA1/2F · 4ma1 jun18 2f · question 24.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.