4MA1/2HR Jun 2020, Question 21: Histograms (Unequal Class Intervals)
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 2HR (Higher) · Calculator · 3 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Using a histogram of restaurant waiting times with unequal class widths, and knowing 14 customers waited under 10 minutes, find how many customers waited under 60 minutes.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Solution · 3 marks
- 10−10 bar: frequency density = 14 ÷ 10 = 1.4, which is 7 small squares, so 1 square = 0.2
- 210−25: 16 squares = 3.2, so 3.2 × 15 = 48
- 325−30: 18 squares = 3.6, so 3.6 × 5 = 18
- 430−40: 0.6 × 10 = 6, and 40−60: 0.2 × 20 = 4
- 5Total = 14 + 48 + 18 + 6 + 4 = 90
Answer90
Stuck on a step? Read the free lesson: Histograms (Unequal Class Intervals)
Practise more histograms (unequal class intervals) questions
Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on histograms (unequal class intervals)
Also searched as: 4MA1 2HR June 2020 · 4MA1/2HR · 4ma1 jun20 2hr · question 21.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.