Lemmara logoLemmaraWorked solution

4MA1/1HR Jun 2022, Question 14: Simultaneous Equations by Elimination

Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1HR (Higher) · Calculator · 4 marks

اقرأ هذا الحل مشروحاً بالعربي ←

The question, in short

Solve the simultaneous equations 3x − 5y = 25 and 4x + 3y = 14, showing clear algebraic working.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Solution · 4 marks

  1. 1Multiply first equation by 3: 9x − 15y = 75
  2. 2Multiply second equation by 5: 20x + 15y = 70
  3. 3Add the equations: 29x = 145
  4. 4x = 145 / 29 = 5
  5. 5Substitute x = 5 into 4x + 3y = 14: 4(5) + 3y = 14
  6. 620 + 3y = 14
  7. 73y = 14 − 20 = −6
  8. 8y = −6 / 3 = −2
  9. 9x = 5
  10. 10y = −2

Answerx = 5, y = −2

Stuck on a step? Read the free lesson: Simultaneous Equations by Elimination

Practise more simultaneous equations by elimination questions

Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.

Practise free on Lemmara

More past-paper questions on simultaneous equations by elimination

Also searched as: 4MA1 1HR June 2022 · 4MA1/1HR · 4ma1 jun22 1hr · question 14.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.