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4MA1/2FR Jun 2022, Question 7: Linear Sequences and Common Difference

Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 2FR (Foundation) · Calculator · 3 marks

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The question, in short

A sequence starts 1, 7, 13, 19, 25. Find the next term, describe the method used, and explain why 188 is not in the sequence.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (ai) · 1 mark

Write down the term that follows 25 in the sequence.

  1. 1The terms are 1, 7, 13, 19, 25.
  2. 27 − 1 = 6, 13 − 7 = 6, 19 − 13 = 6, 25 − 19 = 6
  3. 3Each term is 6 more than the one before.
  4. 425 + 6 = 31

Answer31

Part (aii) · 1 mark

Explain the reasoning used to obtain the next term.

  1. 1The terms are 1, 7, 13, 19, 25.
  2. 27 − 1 = 6, 13 − 7 = 6, 19 − 13 = 6, 25 − 19 = 6
  3. 3The same number, 6, is added each time.
  4. 4So I added 6 to the last term.

Answeradd 6

Part (b) · 1 mark

Give a reason why 188 cannot appear in this sequence.

  1. 1The terms are 1, 7, 13, 19, 25, and each term is 6 more than the one before.
  2. 2Adding 6 to an odd number always gives an odd number, so every term is odd.
  3. 3188 is even.
  4. 4So 188 cannot be a number in the sequence.

Answer188 is even, but every term in the sequence is odd

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