4MA1/1H Jun 2024, Question 16: Tree Diagrams for Dependent Events
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1H (Higher) · Calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
A box holds 20 sweets: 15 red and 5 yellow. Fred picks 3 at random. Find the probability he gets at least one sweet of each colour.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 4 marks
- 1P(at least one of each) = 1 − P(all red) − P(all yellow).
- 2P(all red) = 15/20 × 14/19 × 13/18 = 2730/6840.
- 3P(all yellow) = 5/20 × 4/19 × 3/18 = 60/6840.
- 41 − 2730/6840 − 60/6840 = 4050/6840.
- 54050/6840 = 45/76
Answer45/76
Stuck on a step? Read the free lesson: Tree Diagrams for Dependent Events
Practise more tree diagrams for dependent events questions
Real 4MA1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on tree diagrams for dependent events
Also searched as: 4MA1 1H June 2024 · 4MA1/1H · 4ma1 jun24 1h · question 16.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.