4MA1/1HR Jun 2024, Question 14: Expand and Simplify
Pearson Edexcel International GCSE Mathematics A 4MA1 · Paper 1HR (Higher) · Calculator · 6 marks
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The question, in short
Expand and simplify the product of three linear factors, then simplify a fractional expression with negative indices raised to a negative power.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 3 marks
Expand and simplify (3x + 1)(2 − x)(4 + x).
- 1(3x + 1)(2 − x) = 6x − 3x² + 2 − x = −3x² + 5x + 2
- 2(−3x² + 5x + 2)(4 + x) = −12x² − 3x³ + 20x + 5x² + 8 + 2x
- 3−3x³ + (−12x² + 5x²) + (20x + 2x) + 8
- 4−3x³ − 7x² + 22x + 8
Answer−3x³ − 7x² + 22x + 8
Part (b) · 3 marks
Simplify fully (a³b/(a⁹b⁵))^(−1/2).
- 1(a³b/(a⁹b⁵))^(−1/2) = (a^(3 − 9) b^(1 − 5))^(−1/2) = (a⁻⁶b⁻⁴)^(−1/2)
- 2= a^((−6) × (−1/2)) b^((−4) × (−1/2))
- 3= a³b²
Answera³b²
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