4PM1/02R Jan 2020, Question 11: When a Line Meets, Touches or Misses a Curve
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2R · Calculator · 14 marks
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The question, in short
For the curve y = (3x − 2)/(x + 1), find its asymptotes and axis crossings, sketch it, then use a line y = mx + 4 with no intersection to find integer a and b.
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Part (a) · 2 marks
State the equations of the two asymptotes of C, one parallel to the x-axis and one parallel to the y-axis.
- 1As x → ±∞, y → 3: y = 3
- 2Denominator zero at x = −1: x = −1
Answer(i) y = 3 (ii) x = −1
Part (b) · 2 marks
Find the coordinates where C meets the x-axis and where it meets the y-axis.
- 1y = 0: 3x − 2 = 0, x = 2/3
- 2x = 0: y = −2/1 = −2
Answer(i) (2/3, 0) (ii) (0, −2)
Part (c) · 3 marks
Draw the curve C, clearly marking both asymptotes and the coordinates of its axis crossings.
- 1y = 3 − 5/(x + 1)
- 2Draw asymptotes x = −1 and y = 3
- 3Right branch rises from below through (0, −2) and (2/3, 0) towards y = 3
- 4Left branch lies above y = 3, to the left of x = −1
AnswerTwo-branch hyperbola with asymptotes x = −1 and y = 3; one branch top-left of (−1, 3), the other bottom-right passing through (0, −2) and (2/3, 0)
Part (d) · 7 marks
Given line l with y = mx + 4 misses C, show algebraically that m lies between a − 2√b and a + 2√b, finding integers a and b.
- 1(3x − 2)/(x + 1) = mx + 4
- 23x − 2 = mx² + (m + 4)x + 4, so mx² + (m + 1)x + 6 = 0
- 3No intersections: b² − 4ac < 0, (m + 1)² − 24m < 0
- 4m² − 22m + 1 < 0
- 5Roots m = 11 ± √120 = 11 ± 2√30
- 611 − 2√30 < m < 11 + 2√30
Answer11 − 2√30 < m < 11 + 2√30 (a = 11, b = 30)
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