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4PM1/02 Jun 2020, Question 3: Binomial Series for Any Rational Power

Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2 · Calculator · 5 marks

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The question, in short

Expand (1 + px)^(−5) for p ≠ 0 as a series in ascending powers of x through the x⁴ term, simplifying each term, then use c₄ = 2c₃ to determine p.

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Part (a) · 3 marks

Write the binomial expansion of (1 + px)^(−5) up to and including x⁴, giving every term in simplest form.

  1. 1(1 + px)^(−5) = 1 + (−5)(px) + (−5)(−6)(px)²/2! + (−5)(−6)(−7)(px)³/3! + (−5)(−6)(−7)(−8)(px)⁴/4!
  2. 2= 1 − 5px + 15p²x² − 35p³x³ + 70p⁴x⁴ + …

Answer1 − 5px + 15p²x² − 35p³x³ + 70p⁴x⁴

Part (b) · 2 marks

Given that the x⁴ coefficient equals twice the x³ coefficient, work out the value of p.

  1. 1c₄ = 70p⁴, c₃ = −35p³
  2. 270p⁴ = 2 × (−35p³) ⇒ 70p⁴ + 70p³ = 0
  3. 370p³(p + 1) = 0, p ≠ 0 ⇒ p = −1

Answerp = −1

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