4PM1/01 Jun 2021, Question 11: Definite Integrals and Areas
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 1 · Calculator · 15 marks
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The question, in short
Show a double-angle identity, then find where y = sin x + 2 meets y = cos 2x + 2 at points A, B, C, and compare shaded areas R₁ and R₂.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 3 marks
Show that cos 2x equals 1 − 2sin²x using a formula from page 2.
- 1cos 2x = cos(x + x) = cos x cos x − sin x sin x
- 2= cos²x − sin²x
- 3= (1 − sin²x) − sin²x = 1 − 2sin²x
Answercos 2x = 1 − 2sin²x shown
Part (b) · 4 marks
Find the coordinates of the three intersection points A, B and C of the two curves.
- 1sin x + 2 = cos 2x + 2 ⇒ sin x = 1 − 2sin²x
- 22sin²x + sin x − 1 = 0 ⇒ (2sin x − 1)(sin x + 1) = 0
- 3sin x = 1/2: x = π/6, 5π/6; sin x = −1: x = 3π/2
- 4y = sin x + 2 gives 5/2, 5/2 and 1
AnswerA(π/6, 5/2), B(5π/6, 5/2), C(3π/2, 1)
Part (c) · 8 marks
Use calculus to find the ratio of the area of R₁ to the area of R₂ in simplest form.
- 1R₁ = ∫ from π/6 to 5π/6 of (sin x − cos 2x) dx
- 2= [−cos x − (sin 2x)/2] from π/6 to 5π/6 = 3√3/2
- 3R₂ = ∫ from 5π/6 to 3π/2 of (cos 2x − sin x) dx
- 4= [(sin 2x)/2 + cos x] from 5π/6 to 3π/2 = 3√3/4
- 5R₁ : R₂ = 3√3/2 : 3√3/4 = 2 : 1
Answer2 : 1
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