4PM1/02 Jun 2021, Question 10: Solving Trig Equations
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2 · Calculator · 10 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Solve a tangent equation in degrees, transform a trigonometric identity into a quadratic in tan, then use it to solve a related equation over a full rotation.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 3 marks
Find all x in 0 to 360 satisfying tan x° = −3, rounded to whole degrees.
- 1tan⁻¹(−3) = −71.6°
- 2tan has period 180°: x = −71.6 + 180 = 108.4, x = −71.6 + 360 = 288.4
- 3x = 108, 288
Answerx = 108, 288
Part (b) · 3 marks
Starting from 7sin²θ + sinθcosθ = 6, show it rearranges to tan²θ + tanθ − 6 = 0.
- 17sin²θ + sin θ cos θ = 6(sin²θ + cos²θ)
- 2sin²θ + sin θ cos θ − 6cos²θ = 0
- 3Divide by cos²θ: tan²θ + tan θ − 6 = 0
Answertan²θ + tan θ − 6 = 0 shown
Part (c) · 4 marks
Use the quadratic from part b to solve 7sin²y° + siny°cosy° = 6 for 0 ≤ y < 360, to whole degrees.
- 1tan²y + tan y − 6 = 0 ⇒ (tan y + 3)(tan y − 2) = 0
- 2tan y = −3: y = 108, 288 (from part (a))
- 3tan y = 2: y = 63.4, 243.4
- 4y = 63, 108, 243, 288
Answery = 63, 108, 243, 288
Stuck on a step? Read the free lesson: Solving Trig Equations
Practise more solving trig equations questions
Real 4PM1 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on solving trig equations
Also searched as: 4PM1 2 June 2021 · 4PM1/02 · 4pm1 jun21 2 · question 10.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.