4PM1/02 Nov 2021, Question 9: Trigonometry in 3D: Pyramids and Cones
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 2 · Calculator · 10 marks
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The question, in short
Triangular pyramid ABCD has base ABC with AB = BC = 10 cm, ∠ABC = 90°, and AD = CD = 8 cm. Work out lengths, an angle between planes, and a vertical height.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 2 marks
Calculate AC exactly, giving it as p√q cm with p an integer and q prime.
- 1AC² = 10² + 10² = 200
- 2AC = 10√2 cm
AnswerAC = 10√2 cm
Part (b) · 2 marks
M is the midpoint of AC. Calculate BM exactly as m√n cm, with m and n both prime.
- 1AM = 5√2 and BM ⟂ AC (isosceles triangle)
- 2BM = √(10² − (5√2)²) = √50 = 5√2 cm
AnswerBM = 5√2 cm
Part (c) · 4 marks
Given BD = 6 cm, calculate the acute angle between planes ACD and ABC, in degrees to one decimal place.
- 1DM ⟂ AC: DM = √(8² − (5√2)²) = √14
- 2Required angle is DMB
- 3cos DMB = (14 + 50 − 36)/(2 × √14 × 5√2)
- 4∠DMB = 58.1°
Answer58.1°
Part (d) · 2 marks
With base ABC horizontal, calculate how far D is vertically above the base, in cm to 3 significant figures.
- 1Height = DM sin(∠DMB)
- 2= √14 × sin 58.05…°
- 3= 3.17 cm
Answer3.17 cm (accept 3.18 cm)
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