4PM1/01 Nov 2023, Question 10: Solving Trig Equations
Pearson Edexcel International GCSE Further Pure Mathematics 4PM1 · Paper 1 · Calculator · 17 marks
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The question, in short
Use given formulae to prove double-angle identities, simplify a tangent expression to sin 2θ, solve a trigonometric equation in radians, and evaluate a definite integral using calculus.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 3 marks
Using the formulae on page 2, show the two double-angle identities for sin 2A and cos 2A.
- 1(i) sin(A + A) = sin A cos A + cos A sin A
- 2sin 2A = 2sin A cos A
- 3(ii) cos(A + A) = cos A cos A − sin A sin A = cos²A − sin²A
- 4= cos²A − (1 − cos²A)
- 5= 2cos²A − 1
Answer(i) sin 2A = 2sin A cos A shown; (ii) cos 2A = 2cos²A − 1 shown
Part (b) · 4 marks
Show that f(θ) = 2tan θ/(1 + tan²θ) simplifies to sin 2θ.
- 1f(θ) = (2sin θ/cos θ)/(1 + sin²θ/cos²θ)
- 2Multiply top and bottom by cos²θ: 2sin θ cos θ/(cos²θ + sin²θ)
- 3= 2sin θ cos θ
- 4= sin 2θ
Answerf(θ) = sin 2θ shown
Part (c) · 6 marks
Solve 5tan(x + π/6) = [1 + tan²(x + π/6)][1 − 2cos²(x + π/6)] for −π/2 ≤ x ≤ π/2, radians to 3 significant figures.
- 1Divide by 1 + tan²(x + π/6): 5tan(x + π/6)/(1 + tan²(x + π/6)) = 1 − 2cos²(x + π/6)
- 2Left side = (5/2)sin(2x + π/3) by part (b); right side = −cos(2x + π/3)
- 3(5/2)sin(2x + π/3) = −cos(2x + π/3), so tan(2x + π/3) = −2/5
- 42x + π/3 = −0.38050… or 2.76108…
- 5x = −0.714 or x = 0.857
Answerx = −0.714, x = 0.857
Part (d) · 4 marks
Find the exact value of the integral from 0 to π/2 of 4tan θ/(1 + tan²θ) − cos 5θ + 2 using calculus.
- 14tan θ/(1 + tan²θ) = 2sin 2θ
- 2I = ∫ from 0 to π/2 of (2sin 2θ − cos 5θ + 2) dθ
- 3= [−cos 2θ − (sin 5θ)/5 + 2θ] from 0 to π/2
- 4= (1 − 1/5 + π) − (−1)
- 5= 9/5 + π
Answer9/5 + π
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