WMA11/01 Jan 2019, Question 3: Perpendicular Lines
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 1 (WMA11) · Calculator · 5 marks
The question, in short
For the line 3x + 5y − 7 = 0, work out its gradient, then get the equation of the perpendicular line through (6, −2) as y = mx + c.
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Part (a) · 2 marks
Determine the slope of the line given by 3x + 5y − 7 = 0.
- 1Make y the subject: 5y = −3x + 7
- 2y = −(3/5)x + 7/5, so the gradient is −3/5
Answer−3/5
Part (b) · 3 marks
Find y = mx + c for the line at right angles to l₁ passing through (6, −2).
- 1Perpendicular gradient: m = 5/3
- 2Use the point (6, −2): y + 2 = (5/3)(x − 6)
- 3y = (5/3)x − 10 − 2 = (5/3)x − 12
Answery = (5/3)x − 12
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