WMA11/01 Jan 2024, Question 5: Perpendiculars: Feet and Areas
Pearson Edexcel International AS Level Mathematics · Pure Mathematics 1 (WMA11) · Calculator · 10 marks
The question, in short
Given line l₁ through P(−2, 9) and Q(10, 6), find its equation, the point R where it meets a perpendicular line through O, and the exact area of triangle OPQ.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 3 marks
Find the equation of l₁ in the form y = mx + c, determining constants m and c.
- 1m = (9 − 6)/(−2 − 10) = 3/(−12) = −1/4
- 2y − 9 = −¼(x + 2)
- 3y = −¼x + 17/2
Answery = −¼x + 17/2
Part (b) · 4 marks
Line l₂ through O is perpendicular to l₁; find the coordinates of their intersection R.
- 1Perpendicular gradient = 4, through O: l₂ is y = 4x
- 24x = −¼x + 17/2
- 3(17/4)x = 17/2 ⇒ x = 2
- 4y = 4 × 2 = 8, so R(2, 8)
AnswerR(2, 8)
Part (c) · 3 marks
Find the exact area of triangle OPQ.
- 1OR is perpendicular to PQ, so OR is the height of triangle OPQ
- 2PQ = √(12² + 3²) = √153 = 3√17
- 3OR = √(2² + 8²) = √68 = 2√17
- 4Area = ½ × 3√17 × 2√17 = ½ × 6 × 17 = 51
Answer51
Stuck on a step? Read the free lesson: Perpendiculars: Feet and Areas
Practise more perpendiculars: feet and areas questions
Real XMA01 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on perpendiculars: feet and areas
Also searched as: WMA11 January 2024 · WMA11/01 · wma11 jan24 · IAS Maths Pure Mathematics 1 January 2024 · question 5.
Lemmara is an independent study tool, not affiliated with or endorsed by Pearson Edexcel. The worked solutions are Lemmara’s own.