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Calculating with Bounds

Find the biggest and smallest values of longer formulas made from rounded numbers, and give an answer to a suitable degree of accuracy.

In the exam for Cambridge IGCSE Maths 0580, Edexcel IGCSE Maths 4MA1, Cambridge O Level Maths 4024 · 41 real past-paper questions below

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What Changes in a Longer Formula

Calculating with bounds means a formula with two, three or more rounded numbers. You want the biggest or the smallest answer it could give.

Go one number at a time. Ask: if this number gets bigger, does the answer go up or down?

Where the number isFor the upper bound
added onits upper bound
taken awayits lower bound
multiplied inits upper bound
squared or cubed (a length, a radius)its upper bound
on top of a fractionits upper bound
on the bottomits lower bound

Rule

For the lower bound of the answer, swap every choice.

Bounds of a Formula

The 3-mark question: a formula like . Here , and , all to 2 significant figures. Find the upper bound of , to 1 decimal place.

Worked example

  1. 1

    — 9.6 to 2 s.f. can be 0.05 either way. p is on top, so its upper bound makes the answer biggest.

  2. 2

    — q is taken away. Taking away the smallest q leaves the most, so use its lower bound.

  3. 3

    — 0.35 to 2 s.f. can be 0.005 either way. t is on the bottom, and dividing by a smaller number gives a bigger answer.

  4. 4

    — Put the three chosen bounds into the formula.

  5. 5

    — Work out the top first: 9.65 − 4.05 = 5.6.

  6. 6

    — Divide. Keep every figure on your calculator for now.

  7. 7

    — Round only at the end, to 1 decimal place as the question asks.

Key idea

The 2-mark version is a plain difference. The lower bound of is the lower bound of minus the upper bound of .

Common mistake

Using 4.15 because it is an upper bound question. is taken away, so its lower bound makes the answer bigger.

Squares, Cubes and Exact Numbers

Density and volume questions often cube a rounded length. Find the length's bound first, then cube it.

Formula

is a rounded length, and UB means upper bound. The same works for a square, and for the lower bound: .

A metal cube has mass 52.3 g and side 1.9 cm, both to 1 decimal place. Find the upper bound of its density, to 3 s.f.

Worked example

  1. 1

    — 1 d.p. means 0.05 either way. Mass is on top of density = mass ÷ volume, so use its upper bound.

  2. 2

    — The volume is on the bottom. The shortest side gives the smallest volume, and a smaller bottom gives a bigger answer.

  3. 3

    — Cube the bound, not the rounded 1.9. Volume of a cube is side × side × side.

  4. 4

    — Divide mass by volume, keeping every figure.

  5. 5

    — Round at the end, to 3 s.f.

Key idea

Exact numbers have no bounds: a count like 8 boxes, “exactly 2 hours”, π, or the 2 in 2a. Use them as they are. Eight boxes of 12 kg, to the nearest kg, weigh at least kg.

Common mistake

Cubing first, then taking off 0.05: , then 6.809. Bound the side first, then cube it.

A Suitable Degree of Accuracy

The 4-mark question: "work out the value to a suitable degree of accuracy". Find both bounds, then round both until they agree.

A runner covers 452 metres, to the nearest metre, in 51.3 seconds, to 1 decimal place. Find the speed.

Worked example

  1. 1

    — To the nearest metre means half a metre either way.

  2. 2

    — To 1 decimal place means 0.05 either way.

  3. 3

    — The most distance in the least time gives the fastest possible speed.

  4. 4

    — The least distance in the most time gives the slowest possible speed.

  5. 5

    — Round both the same way. They differ, so 3 s.f. is not safe.

  6. 6

    — Try one figure fewer. Now they agree, so the true speed must round to 8.8.

  7. 7

    — Give the answer with the reason: both bounds round to 8.8 to 2 s.f.

Rule

Round the upper and the lower bound the same way. Your answer is the most accurate rounding where they agree.

Common mistake

Giving 8.83, or rounding only one bound. Write both bounds and say they both round to 8.8.

Bounds in a Triangle

The 4-mark question: a triangle with a rounded side and rounded angles. Use the sine rule, then choose each bound.

Formula

Here and are sides, and and are the angles opposite them.

Side cm to 1 decimal place. Angles and to the nearest degree. Find the upper bound of .

Worked example

  1. 1

    — 9.5 to 1 d.p. can be 0.05 either way. c is on top, so use its upper bound.

  2. 2

    — To the nearest degree means 0.5° either way. sin B is on top, and a bigger angle (below 90°) has a bigger sine.

  3. 3

    — sin C is on the bottom. The smaller angle gives a smaller sine, and dividing by less gives more.

  4. 4

    — Put the three chosen bounds into the sine rule.

  5. 5

    — Work out the top and the bottom on your calculator, in degree mode.

  6. 6

    — Divide. Keep every figure for now.

  7. 7

    — Round only at the end, to 3 significant figures.

Key idea

For angles below 90°, a bigger angle gives a bigger sine. Cosine goes the other way: a bigger angle gives a smaller cosine.

Common mistake

Using 55.5° on the bottom. A bigger bottom makes the answer smaller.

Bounds of an Angle

Some questions want the bound of an angle found with or . Bound the fraction first: a bigger fraction gives a bigger angle.

A ramp is 1.8 m high and its sloping length is 7.4 m, both to 1 decimal place. Find the lower bound of the angle the ramp makes with the ground.

Worked example

  1. 1

    — The height is opposite the angle and the slope is the hypotenuse. To make the angle smallest, make this fraction smallest.

  2. 2

    — The height is on top, so use its lower bound. 1 d.p. means 0.05 either way.

  3. 3

    — The slope is on the bottom, so use its upper bound. A bigger bottom makes the fraction smaller.

  4. 4

    — Divide, keeping every figure.

  5. 5

    — Use the inverse sine key to turn the fraction into an angle.

  6. 6

    — Round at the end, to 3 s.f.

Key idea

An angle found as works like a difference. Its upper bound uses the lower bounds of x and y.

Common mistake

Making the same choice with . For cosine a bigger fraction gives a smaller angle, so swap your choices.

How Many Fit? Round Down or Up

“What is the largest number of pieces?” and “how many tins must she buy?” need a whole number at the end. Choose the bounds, then round the right way.

A rope is 95 m long, to the nearest metre. It is cut into pieces 1.6 m long, to the nearest 10 cm. Find the largest possible number of pieces.

Worked example

  1. 1

    — To the nearest metre means half a metre either way. The longest rope gives the most pieces.

  2. 2

    — To the nearest 10 cm means 5 cm, or 0.05 m, either way. The shortest pieces give the most pieces.

  3. 3

    — Divide the most rope by the shortest piece.

  4. 4

    — Round down. The 0.61 is only part of a piece, so it does not count.

Key idea

For the least number of tins of paint you must buy to be sure, use the biggest area and the least that one tin covers. Then round up: a part-used tin still has to be bought.

Common mistake

Rounding 61.61 to 62. You cannot cut 62 whole pieces, so the answer is 61.

Which Method? Read the Question

Take each rounded number, find its bounds, then read what the question wants.

You seeYou do
Upper bound of a formulaeach number: which bound pushes it up
Lower bound of a formulaswap every choice
Lower bound of lower e, upper f
A suitable degree of accuracyboth bounds, round until they agree
A triangle with rounded anglesbound each angle, then the sine rule
A cube or square of a rounded lengthbound the length, then cube or square it
An angle from or bound the fraction first
The largest number of piecesmost ÷ least, then round down
A time in minutes, a speed in km/hbound the minutes, then divide by 60
Write down one boundUpper and Lower Bounds

Key idea

Keep every figure on your calculator until the end. Round only the final answer.

Key idea

Write down every bound you use before you calculate. Each correct bound can earn a mark, even if the final answer goes wrong.

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