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Expressing Vectors in Terms of a and b

Find any vector in a shape as a route of known sides: parallelograms, trapeziums, regular hexagons and points part way along a side.

In the exam for Cambridge O Level Maths 4024, Cambridge IGCSE Maths 0580, Edexcel Further Pure Maths 4PM1, Edexcel IGCSE Maths 4MA1, IGCSE Additional Maths 0606 · 62 real past-paper questions below

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Routes Through a Shape

You can only use the vectors you are given. To find a new vector, walk from its start to its end along sides you know.

You walkYou write
along an arrowplus that vector
against an arrowminus that vector
a parallel side, same lengththe same vector
a parallel side, twice as long2 times the vector

Rule

Any route works: . Pick the one through sides you know.

Parallelograms: Opposite Sides Match

In a parallelogram, opposite sides are equal and parallel, so they are the same vector.

Worked example

  1. 1

    — The parallelogram is OABC. We are given the two sides that start at O.

  2. 2

    — AB is opposite OC. Opposite sides of a parallelogram are equal and parallel, so AB is the same vector .

  3. 3

    — To get from O to B, go along OA, then along AB.

  4. 4

    — Put in and .

  5. 5

    — For the other diagonal, go from A back to O, then out to C.

  6. 6

    — A to O goes against the arrow for OA, so it has a minus.

  7. 7

    — Put in and .

  8. 8

    — Write the positive term first. It is the same vector and easier to read.

Common mistake

Writing a − b for AC. Check the first step: from A to O goes against a, so it is −a.

Trapeziums: Parallel Sides Are Multiples

In a trapezium, one pair of sides is parallel but the lengths differ. The longer one is a number times the shorter one.

Worked example

  1. 1

    — The trapezium is OABC. We are given the two sides that start at O.

  2. 2

    — Given: AB is parallel to OC and twice as long, so it is 2 lots of , pointing the same way.

  3. 3

    — From C to B, go back to O, along to A, then along to B. All three sides are known.

  4. 4

    — C to O goes against the arrow for OC, so it has a minus.

  5. 5

    — Put in CO, OA and AB.

  6. 6

    — Collect the terms: , so one .

Common mistake

Using b for AB. The side is parallel to OC but twice as long, so it is 2b.

Regular Hexagons

The 4-mark question uses a regular hexagon. Two facts do most of the work.

FactVector
Opposite sides are parallelDE is the reverse of AB
A long diagonal is parallel to two sidestwice as long as each of them

Worked example

  1. 1

    — A regular hexagon has equal sides and equal angles. We are given two sides that follow each other.

  2. 2

    — AD is a long diagonal. It is parallel to BC and twice as long.

  3. 3

    — DE is the side opposite AB. It is equal and parallel, but points the other way, so it has a minus.

  4. 4

    — To get from A to E, go along the long diagonal to D, then along DE.

  5. 5

    — Put in and .

  6. 6

    — Adding is the same as taking away .

Common mistake

Going round the edge one side at a time. It works, but the long diagonal is much quicker and has fewer signs to get wrong.

A Point Part of the Way Along a Side

When a point splits a side in a ratio, turn the ratio into a fraction of the whole side first.

Worked example

  1. 1

    — What we are given. M splits AB in the ratio 1 : 3.

  2. 2

    — First find the whole side. Go from A back to O, then out to B.

  3. 3

    — A to O goes against OA, so it is . O to B is .

  4. 4

    — Add the ratio numbers to find how many equal parts AB has.

  5. 5

    — AM is 1 part out of 4, so it is one quarter of AB.

  6. 6

    — To get from O to M, go along OA, then along AM.

  7. 7

    — Put in and the AM we just found.

  8. 8

    — Multiply out the bracket.

  9. 9

    — Collect the terms: .

Now with numbers in front of the letters, and a ratio that does not start with 1.

Worked example

  1. 1

    — Keep each number with its letter. X splits AB in the ratio 3 : 2.

  2. 2

    — A back to O is , then O to B is .

  3. 3

    — Add the ratio numbers to find the total number of parts.

  4. 4

    — AX is 3 parts out of 5, so it is three fifths of AB.

  5. 5

    — Multiply out: and .

  6. 6

    — To get from O to X, go along OA, then along AX.

  7. 7

    — Put in and the AX we just found.

  8. 8

    — Collect the terms: .

Common mistake

Using one third for a ratio of 1 : 3. There are 4 parts in total, so AM is one quarter of AB.

Key idea

A midpoint is the ratio . Take half of the side: , so .

Which Method? Read the Question

Look at the shape and what it tells you about the sides.

You seeYou do
Parallelogramopposite sides are the same vector
Trapezium, one side k times anotheruse k times the vector
Regular hexagonuse the long diagonal
A point in a ratio on a sideturn the ratio into a fraction
Two lines cross, find a ratioVector Geometry
Prove parallel or a straight lineVector Proofs

Key idea

Write every answer in its simplest form: collect the a terms, then the b terms.

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