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Finding the Equation From a Graph

Read where a drawn line crosses the y-axis and how steep it is, then write its equation as y = mx + c.

In the exam for Cambridge IGCSE Maths 0580, Edexcel IGCSE Maths 4MA1 · 11 real past-paper questions below

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Two Things to Read

Every straight line (except an upright one) has an equation of this form:

Formula

To find it from a graph you read just two numbers:

LetterWhat it isWhere to look
the gradient: how steepup ÷ across between two points
the y-interceptwhere the line crosses the y-axis

Key idea

For more on what m and c mean, see The Equation y = mx + c.

Read c, Then m

The 2–3 mark question: a line is drawn on a grid, find its equation. Pick two points where the line crosses grid corners exactly.

Worked example

  1. 1

    — Find where the line cuts the upright axis. That height is c, so c = 2.

  2. 2

    — Pick two points where the line passes exactly through a grid corner. Exact points give an exact gradient.

  3. 3

    — y goes from 2 down to −4. Going down means up is negative: −6.

  4. 4

    — x goes from 0 to 2, so the line moves 2 to the right.

  5. 5

    — Gradient = up ÷ across. Negative, which matches a line going down to the right.

  6. 6

    — Put m in front of x and c on its own, as in .

  7. 7

    — Check with the second point. It gives y = −4, so the equation fits.

Common mistake

Writing . The line goes down to the right, so the gradient must be negative.

Key idea

Show up ÷ across in your working, and write the answer as , not . A correct gradient or a correct c still earns a mark, even if the other one is wrong.

When the Gradient Is a Fraction

Some lines rise slowly. Count across to the next exact grid corner: the gradient is then a fraction.

Worked example

  1. 1

    — The line cuts the y-axis below 0, at −1. So c = −1, minus sign included.

  2. 2

    — Move right from (0, −1) until the line passes exactly through a grid corner. The first one is (3, 1).

  3. 3

    — y goes from −1 up to 1. Taking away a negative adds, so 1 + 1 = 2.

  4. 4

    — x goes from 0 to 3, so the line moves 3 to the right.

  5. 5

    — Up ÷ across. 2 does not divide exactly by 3, so leave the gradient as a fraction.

  6. 6

    — Put m and c into . The −1 keeps its minus.

Common mistake

Doing across ÷ up and getting . Up always goes on top.

Key idea

Check with a third point. At : . It fits.

When One Square Is Not 1

Exams often use axes where one square is not 1. Read the numbers on the axes, never just count squares.

Worked example

  1. 1

    — Read the scales first. Here 5 squares reach 10 on the x-axis, and 2 squares reach 1 on the y-axis.

  2. 2

    — The line crosses the y-axis at the number 3. Read the label, not the square count.

  3. 3

    — Pick a second point where the line passes exactly through a grid corner, and read both numbers off the axes.

  4. 4

    — Use the axis numbers. It is 4 squares, but each square is 0.5, so up = 2.

  5. 5

    — Also 4 squares, but each square is 2, so across = 8.

  6. 6

    — Up ÷ across, then simplify. 2 ÷ 8 = 0.25, which is the same as .

  7. 7

    — Put m and c into .

  8. 8

    — Check with a point on the line, (4, 4). It fits.

Common mistake

Counting squares: 4 up and 4 across gives . That is only right when both scales are the same.

Which Method? Read the Question

Look at the line and what the question asks.

You seeYou do
A sloping line drawn on a gridread c, then up ÷ across
A flat line the height it sits at
An upright line where it crosses the x-axis
A sloping line through c = 0, so
A line that does not reach the y-axisfind m, then put a point in for c: Equation of a Line Through Two Points
Only two points, no graphEquation of a Line Through Two Points
“Draw the line”Drawing Straight-Line Graphs

Key idea

Check the axis scales before counting squares. One square is not always 1.

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Real past-paper questions on finding the equation from a graph

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