Reverse Percentages
Find the original amount before a percentage increase or decrease by dividing by the multiplier, including when you only know part of the whole.
In the exam for Edexcel IGCSE Maths 4MA1, Cambridge IGCSE Maths 0580, Cambridge O Level Maths 4024 · 71 real past-paper questions below
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What a Reverse Percentage Is
You are given the amount AFTER a percentage change. You must find the amount BEFORE it: the original.
The original is always 100%. Work out what percentage you are holding now, then write it as a multiplier.
| Change | You now hold |
| 25% off | 75%, so |
| up 20% | 120%, so |
| down 6% | 94%, so |
| up 8% | 108%, so |
Rule
Going forwards you multiply by the multiplier. Going backwards you divide by it.
Undo a Decrease
The 3-mark question: a sale price, a new salary or a value after it went down. Find the normal price or the value before.
Worked example
- 1
— The question: after 25% off, a price is $51. The original is always 100%. 25% was taken off, so $51 is 75% of the original.
- 2
— 75% as a decimal is 75 ÷ 100 = 0.75. This is the number the original was multiplied by.
- 3
— Write the equation: the original times the multiplier gave the sale price. This line alone earns a mark for working.
- 4
— Multiplying by 0.75 got you to $51, so divide by 0.75 to go back. Dividing undoes multiplying.
- 5
— The normal price. It is bigger than $51, which makes sense: the price went down to reach $51.
- 6
— Multiply forwards. You get the sale price back, so $68 is right.
Common mistake
Adding 25% of $51 back on gives $63.75. Wrong: the 25% was taken from the original, not from $51.
Key idea
Asked for the discount? Find the original first, then subtract: 68 − 51 = $17.
Undo an Increase
The 3-mark question: a price or salary went up, and you know the new amount. Find the amount before the increase.
Worked example
- 1
— The question: a salary went up 20% to $31 200. The old salary is 100%. 20% was added, so $31 200 is 120% of it.
- 2
— 120% as a decimal is 120 ÷ 100 = 1.2. A multiplier bigger than 1 means an increase.
- 3
— Write the equation: the old salary times 1.2 gave the new salary.
- 4
— Divide by 1.2 to undo the multiply and go back to the start.
- 5
— The old salary. It is smaller than $31 200, which makes sense before a rise.
- 6
— Multiply forwards. You get the new salary back, so the answer is right.
Common mistake
Taking 20% off $31 200 gives $24 960. Wrong: the 20% was worked out on the old salary, not the new one.
Key idea
If the question says 3 significant figures, round only at the very end.
No Calculator? Find 10% First
On a non-calculator paper, dividing by 0.7 is hard. Find 10% first, then build up to 100%.
Worked example
- 1
— The question: after 30% off, a coat costs $63. So $63 is 70% of the normal price.
- 2
— Write down what you know. This is the line that earns the first mark.
- 3
— 70% is 7 lots of 10%, so divide by 7 to find 10%.
- 4
— 100% is 10 lots of 10%, so multiply by 10. This is the normal price.
- 5
— 30% of $90 is $27, and $90 − $27 = $63. It works.
Key idea
If the percentage is not a multiple of 10, find 1% instead. If 104% is $624, then 1% = 624 ÷ 104 = $6, so 100% = 6 × 100 = $600.
Common mistake
Finding 30% of $63 and adding it on. The 30% was taken from the normal price, not from $63.
When You Know Part of the Whole
The 2 or 3-mark question: you are told a part and what percentage of the whole it is. Find the whole.
Worked example
- 1
— The question. 91 is only part of the number, so the number must be bigger than 91.
- 2
— 35% as a decimal is 0.35. “35% of” means “0.35 times”.
- 3
— Divide by 0.35 to undo the multiply.
- 4
— The whole number. Check: 0.35 × 260 = 91.
Sometimes you are told the size of the change, not the new amount. Then the change is the part.
Worked example
- 1
— The question: a pay rise of $900 was a 12% rise. The $900 is the 12% itself, not the new salary.
- 2
— 12% as a decimal is 0.12. 12% of the old salary is $900.
- 3
— Divide by 0.12 to undo the multiply.
- 4
— The old salary. Check: 0.12 × 7500 = 900.
- 5
— Only if the question asks for the new salary: add the rise to the old salary.
Common mistake
Multiplying 91 by 0.35 gives 31.85. That makes it smaller, but the whole must be bigger than the part.
Common mistake
Dividing $900 by 1.12 gives $803.57. Wrong: $900 is the 12% rise itself, so divide by 0.12.
Two Changes, Then Go Back
The 3-mark question: two changes in a row, and you know the final value. Find the value at the start.
Worked example
- 1
— The question: a price went up 10%, then down 20%, and is now $264. Up 10% means 110%, so the first multiplier is 1.1.
- 2
— Down 20% leaves 80% of the new price, so the second multiplier is 0.8.
- 3
— Multiply the two multipliers. This gives one multiplier that does both changes at once.
- 4
— Write the equation: the start price times 0.88 gave $264.
- 5
— Divide by 0.88 to undo both changes in one go.
- 6
— The start price. Check: 300 × 1.1 = 330, then 330 × 0.8 = 264.
Common mistake
Treating it as a 10% fall and dividing by 0.9 gives $293.33. Multiply the two multipliers instead.
Key idea
The same works for “percent of what is left”. 20% of some coins are gold, 25% of the rest are silver, and the other 120 are copper. Copper is 0.8 × 0.75 = 0.6 of all the coins, so there are 120 ÷ 0.6 = 200 coins.
Which Method? Read the Question
Ask yourself: do I know the amount before the change, or after it?
| You see | You do |
| the price after 15% off, find the normal price | divide by 0.85 |
| after an increase of 8%, find the price before | divide by 1.08 |
| 40% of a number is 58 | divide by 0.4 |
| up, then down, find the start | divide by both multipliers multiplied |
| a price includes 15% tax, find it without tax | divide by 1.15 |
| how much more, or how much was taken off | find the original first, then subtract |
| you know the original, find the new amount | Percentage Increases and Decreases |
| the same percentage each year for several years | Compound Interest |
Key idea
Check your answer: before a decrease the original must be bigger; before an increase it must be smaller.
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