0580/22 Feb/Mar 2023, Question 10: Similar Triangles
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 3 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Parallel lines AB and CD with lines crossing at X give two similar triangles; with AB 3.0, AX 2.0, BX 2.7 and CD 7.5 cm, find the length BC.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Solution · 3 marks
- 1Triangles ABX and DCX are similar (AB parallel to CD)
- 2XC/BX = CD/AB, so XC = 2.7 × 7.5 ÷ 3 = 6.75 cm
- 3BC = 2.7 + 6.75 = 9.45 cm
Answer9.45
Stuck on a step? Read the free lesson: Similar Triangles
Practise more similar triangles questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on similar triangles
Also searched as: 0580/22/F/M/23 · 0580_m23_qp_22 · 0580 m23 22 · question 10.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.