0580/12 Feb/Mar 2025, Question 26: Simultaneous Equations by Elimination
Cambridge IGCSE Mathematics 0580 · Paper 12 (Core) · Non-calculator · 4 marks
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The question, in short
Solve the pair of simultaneous equations 4t − 3w = 11 and 6t + 2w = −3, finding the values of t and w.
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Solution · 4 marks
- 1× 2: 8t − 6w = 22; × 3: 18t + 6w = −9
- 2Add: 26t = 13, so t = 0.5
- 34(0.5) − 3w = 11 → 2 − 3w = 11
- 4−3w = 9, so w = −3
Answert = 0.5, w = −3
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