0580/23 May/Jun 2021, Question 22: Inverse Proportion: y = k/x
Cambridge IGCSE Mathematics 0580 · Paper 23 (Extended) · Calculator · 2 marks
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The question, in short
Given z varies inversely as the square of (y − 2), and z = 9 when y = 5, find an equation for z in terms of y.
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Solution · 2 marks
- 1z = k/(y − 2)²
- 29 = k/(5 − 2)² = k/9
- 3k = 81
- 4z = 81/(y − 2)²
Answer81/(y − 2)²
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Also searched as: 0580/23/M/J/21 · 0580_s21_qp_23 · 0580 s21 23 · question 22.
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