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0580/43 May/Jun 2023, Question 1: Profit and Loss

Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 11 marks

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The question, in short

Work through ratio, percentage profit, simple interest and sale-price problems involving Tomas's sales, Ulla's investment and Victor's shoes.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (ai) · 2 marks

Find the phone amount as a percentage of the total, given the ratio 14 : 17 : 9.

  1. 1Total parts = 14 + 17 + 9 = 40
  2. 2Phone = 9/40 × 100
  3. 3= 22.5%

Answer22.5

Part (aii) · 2 marks

With total $560, calculate the amount received for the bike from the ratio.

  1. 1Total parts = 14 + 17 + 9 = 40
  2. 2One part = 560 ÷ 40 = 14
  3. 3Bike gets 17 parts: 17 × 14 = 238

Answer238

Part (aiii) · 3 marks

Bike bought for $195, sold for the bike amount from $560; decide if profit is at least 25%, showing working.

  1. 1Total $560 in 40 parts, so the bike gets 560 ÷ 40 × 17 = $238
  2. 2Price needed for 25% profit = 1.25 × 195 = $243.75
  3. 3238 < 243.75, so No

Answer243.75 needed, 238 < 243.75 so No

Part (b) · 2 marks

Calculate simple interest on $725 at 1.3% per year over 6 years.

  1. 1Interest = 725 × 1.3/100 × 6
  2. 2= $56.55

Answer56.55

Part (c) · 2 marks

After a 24% reduction Victor pays $36.86; find the original price of the shoes.

  1. 1Sale price = 76% of original
  2. 2Original = 36.86 ÷ 0.76
  3. 3= $48.50

Answer48.50

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Also searched as: 0580/43/M/J/23 · 0580_s23_qp_43 · 0580 s23 43 · question 1.
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