0580/21 May/Jun 2024, Question 12: Simultaneous Equations by Elimination
Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Calculator · 4 marks
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The question, in short
Solve the simultaneous equations 3x/2 + 5y = 5 and 4x − 3y = 46, showing all working.
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Solution · 4 marks
- 1Multiply the first equation by 2: 3x + 10y = 10
- 2×4: 12x + 40y = 40 and second equation ×3: 12x − 9y = 138
- 3Subtract: 49y = −98, so y = −2
- 44x − 3(−2) = 46 → 4x = 40 → x = 10
- 5x = 10, y = −2
Answerx = 10, y = −2
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Also searched as: 0580/21/M/J/24 · 0580_s24_qp_21 · 0580 s24 21 · question 12.
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