0580/32 May/Jun 2024, Question 7: Percentage Increases and Decreases

Part (a) · 3 marks

Use the ratio 11:2:3 and the park's 4620 m² to find the gardens' and playground's areas.

1. 1One part = 4620 ÷ 11 = 420
2. 2Gardens = 2 × 420 = 840 m²
3. 3Playground = 3 × 420 = 1260 m²

AnswerGardens 840, Playground 1260

Part (bi) · 1 mark

With 18% of the 4620 m² park being paths, show the grassland area equals 3788.4 m².

1. 1Grassland = (100 − 18)/100 × 4620
2. 2= 0.82 × 4620 = 3788.4 m²

Answer(100 − 18)/100 × 4620

Part (bii) · 4 marks

Seed bags cover 280 m² each; first 5 cost $72, extras $58. Calculate total seed cost for the grassland.

1. 13788.4 ÷ 280 = 13.53…, so 14 bags
2. 2First 5 bags: 5 × 72 = $360
3. 3Extra 9 bags: 9 × 58 = $522
4. 4Total = 360 + 522 = $882

Answer882

Part (c) · 3 marks

Find the repayment after borrowing $8500 for 4 years at 6.5% yearly compound interest, to the nearest dollar.

1. 1Amount = 8500 × (1 + 6.5/100)⁴
2. 2= 8500 × 1.065⁴ = 10934.96…
3. 3≈ $10935

Answer10935

Part (d) · 3 marks

Compare bottles A (330 ml, $1.98), B (500 ml, $3.20) and C (750 ml, $5.10) to determine best value, showing working.

1. 1A: 1.98 ÷ 330 = $0.0060 per ml
2. 2B: 3.20 ÷ 500 = $0.0064 per ml
3. 3C: 5.10 ÷ 750 = $0.0068 per ml
4. 4A is cheapest per ml, so A is the best value

AnswerA

More past-paper questions on percentage increases and decreases

• 0580/13 May/Jun 2026 Q15 · 4 marks
• 0580/22 Feb/Mar 2025 Q11 · 10 marks
• 0580/32 Feb/Mar 2025 Q18 · 5 marks
• 0580/13 May/Jun 2025 Q16 · 3 marks
• 0580/31 May/Jun 2025 Q23 · 2 marks
• 0580/32 May/Jun 2025 Q18 · 4 marks