0580/22 May/Jun 2025, Question 13: Estimating the Mean for Grouped Data
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Non-calculator · 11 marks
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The question, in short
From grouped time data for 100 students and cumulative frequency data for 80 adults solving a puzzle, estimate mean, complete a histogram, draw a cumulative frequency diagram, and estimate median and lower quartile.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 4 marks
Calculate an estimated mean time from the grouped frequency table for the 100 students.
- 1Midpoints: 30, 50, 80
- 2Σfx = 30 × 30 + 40 × 50 + 30 × 80 = 900 + 2000 + 2400 = 5300
- 3Mean = 5300 ÷ 100 = 53 s
Answer53
Part (aii) · 2 marks
Complete the histogram by drawing bars for the remaining time intervals using frequency density.
- 140 < t ≤ 60: frequency density = 40 ÷ 20 = 2
- 260 < t ≤ 100: frequency density = 30 ÷ 40 = 0.75
- 3Draw a bar from 40 to 60 of height 2 and a bar from 60 to 100 of height 0.75
AnswerTwo correct bars with correct widths and heights 2 and 0.75
Part (bi) · 3 marks
Plot a cumulative frequency curve for the 80 adults on the given grid.
- 1Plot (20, 0), (40, 12), (60, 36), (80, 60), (100, 74), (120, 80) at the upper class boundaries
- 2Join the points with a smooth increasing curve
AnswerCorrect diagram
Part (biia) · 1 mark
Use the cumulative frequency diagram to estimate the median time for the adults.
- 1Median at cumulative frequency 80 ÷ 2 = 40
- 2Between (60, 36) and (80, 60): 60 + 4/24 × 20 ≈ 63
- 3Median ≈ 63 s
Answer62 to 64
Part (biib) · 1 mark
Use the cumulative frequency diagram to estimate the lower quartile time for the adults.
- 1Lower quartile at cumulative frequency 80 ÷ 4 = 20
- 2Between (40, 12) and (60, 36): 40 + 8/24 × 20 ≈ 47
- 3Lower quartile ≈ 47 s
Answer46 to 48
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