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0580/22 May/Jun 2025, Question 22: Trigonometric Graphs and Equations

Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Non-calculator · 4 marks

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The question, in short

Find the exact value of tan 60°, then solve the equation 2 sin x − 1 = 0 for x between 0° and 360°.

Summarised in our own words. Use the official paper for the exact wording and any diagrams.

Part (a) · 1 mark

State the exact value of tan 60°.

  1. 1tan 60° = √3

Answer√3

Part (b) · 3 marks

Solve 2 sin x − 1 = 0 for 0° ≤ x ≤ 360°, giving all values of x.

  1. 12 sin x = 1, so sin x = 1/2
  2. 2x = 30°
  3. 3x = 180 − 30 = 150°
  4. 4x = 30, 150

Answer30, 150

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Also searched as: 0580/22/M/J/25 · 0580_s25_qp_22 · 0580 s25 22 · question 22.
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