0580/21 Oct/Nov 2025, Question 26: Trigonometric Graphs and Equations
Cambridge IGCSE Mathematics 0580 · Paper 21 (Extended) · Non-calculator · 3 marks
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The question, in short
Solve tan x = −1/√3 for x in the range 0° to 360°, giving all solutions in that interval.
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Solution · 3 marks
- 1tan⁻¹(1/√3) = 30°
- 2tan x is negative in the 2nd and 4th quadrants
- 3x = 180 − 30 = 150° and x = 360 − 30 = 330°
Answer150 and 330
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