0580/13 Oct/Nov 2022, Question 18: Pythagoras' Theorem
Cambridge IGCSE Mathematics 0580 · Paper 13 (Core) · Calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Right-angled triangle with hypotenuse 14 cm and base 10 cm; find the vertical side h and then the triangle's perimeter.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 3 marks
Use Pythagoras with hypotenuse 14 cm and base 10 cm to calculate the vertical side h.
- 110² + h² = 14²
- 2h² = 196 − 100 = 96
- 3h = √96 = 9.797… ≈ 9.80
Answer9.80 or 9.797 to 9.798
Part (b) · 1 mark
Add the three side lengths, including the h found in part a, to get the perimeter.
- 1Perimeter = 14 + 10 + 9.797… = 33.797… ≈ 33.8 cm
Answer33.8 or 33.79 to 33.80
Stuck on a step? Read the free lesson: Pythagoras' Theorem
Practise more pythagoras' theorem questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on pythagoras' theorem
Also searched as: 0580/13/O/N/22 · 0580_w22_qp_13 · 0580 w22 13 · question 18.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.