0580/22 Oct/Nov 2022, Question 19: Conditional Probability
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 3 marks
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The question, in short
Katy randomly selects one value from 2, 3, 5 and another from 5, 6, 7, 9; given their total is even, work out the chance that precisely one chosen value equals 5.
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Solution · 3 marks
- 1Even totals: 2+6, 3+5, 3+7, 3+9, 5+5, 5+7, 5+9 → 7 outcomes
- 2Exactly one 5: 3+5, 5+7, 5+9 → 3 outcomes
- 3Probability = 3/7
Answer3/7
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