0580/22 Oct/Nov 2023, Question 25: Differentiating Polynomials
Cambridge IGCSE Mathematics 0580 · Paper 22 (Extended) · Calculator · 2 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Given the derivative 42x⁶ + 15xᵏ⁻¹ of 2ax⁷ + 3xᵏ, find the constants a and k.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 2 marks
- 1Derivative = 2a × 7x⁶ + 3kxᵏ⁻¹ = 14ax⁶ + 3kxᵏ⁻¹
- 214a = 42 → a = 3
- 33k = 15 → k = 5
- 4a = 3, k = 5
Answera = 3, k = 5
Stuck on a step? Read the free lesson: Differentiating Polynomials
Practise more differentiating polynomials questions
Real 0580 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on differentiating polynomials
Also searched as: 0580/22/O/N/23 · 0580_w23_qp_22 · 0580 w23 22 · question 25.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.