0580/43 Oct/Nov 2024, Question 2: Negative Enlargement
Cambridge IGCSE Mathematics 0580 · Paper 43 (Extended) · Calculator · 12 marks
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The question, in short
Given points A(3, 7) and B(−1, 5), work out the midpoint of AB, the column vector for AB, and point C where AC = 3BA; then perform transformations on shape P on a grid.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (ai) · 2 marks
Work out the coordinates of the point halfway between A(3, 7) and B(−1, 5).
- 1x = (3 + (−1)) ÷ 2 = 1
- 2y = (7 + 5) ÷ 2 = 6
- 3Midpoint (1, 6)
Answer(1, 6)
Part (aii) · 1 mark
Express the displacement from A to B as a column vector.
- 1→AB = B − A = (−1 − 3, 5 − 7)
- 2= column vector (−4, −2)
Answercolumn vector (−4, −2)
Part (aiii) · 2 marks
Given AC = 3BA, work out the coordinates of point C.
- 1→BA = column vector (4, 2)
- 2→AC = 3→BA = column vector (12, 6)
- 3C = (3 + 12, 7 + 6) = (15, 13)
Answer(15, 13)
Part (bi) · 2 marks
Turn shape P by 180° around the point (4, 1) and draw the result.
- 1Each point (x, y) maps to (8 − x, 2 − y)
- 2(1, 1)→(7, 1), (4, 1)→(4, 1), (3, 3)→(5, −1), (1, 3)→(7, −1)
- 3Join (4, 1), (5, −1), (7, −1), (7, 1)
AnswerImage at (4, 1), (5, −1), (7, −1), (7, 1)
Part (bii) · 2 marks
Mirror shape P in the line y = x + 2 and draw the image.
- 1Draw the line y = x + 2 through (0, 2) and (1, 3)
- 2Each point (x, y) maps to (y − 2, x + 2)
- 3(1, 1)→(−1, 3), (4, 1)→(−1, 6), (3, 3)→(1, 5), (1, 3)→(1, 3)
- 4Join (1, 3), (−1, 3), (−1, 6), (1, 5)
AnswerImage at (1, 3), (−1, 3), (−1, 6), (1, 5)
Part (biii) · 3 marks
State fully the one transformation taking shape P onto shape Q.
- 1Q is inverted and half the size of P, so scale factor −1/2
- 2Lines joining (1, 1)→(4, 4) and (4, 1)→(2.5, 4) cross at (3, 3)
- 3Enlargement, centre (3, 3), scale factor −1/2
AnswerEnlargement, centre (3, 3), scale factor −1/2
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Also searched as: 0580/43/O/N/24 · 0580_w24_qp_43 · 0580 w24 43 · question 2.
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