0580/41 Oct/Nov 2025, Question 26: Simultaneous equations (one quadratic)
Cambridge IGCSE Mathematics 0580 · Paper 41 (Extended) · Calculator · 4 marks
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The question, in short
Solve y = 2x² − 3x − 7 and y = 2x − 7 simultaneously.
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Solution · 4 marks
- 12x² − 3x − 7 = 2x − 7
- 22x² − 5x = 0
- 3x(2x − 5) = 0, so x = 0 or x = 2.5
- 4x = 0: y = 2 × 0 − 7 = −7; x = 2.5: y = 2 × 2.5 − 7 = −2
- 5x = 0, y = −7 and x = 2.5, y = −2
Answerx = 0, y = −7 and x = 2.5, y = −2
Stuck on a step? Read the free lesson: Simultaneous Equations by Elimination
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Also searched as: 0580/41/O/N/25 · 0580_w25_qp_41 · 0580 w25 41 · question 26.
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