0606/12 Feb/Mar 2025, Question 3: The Equation of a Circle
Cambridge IGCSE Additional Mathematics 0606 · Paper 12 (Non-calculator) · Non-calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
Using A(−3, 6) and B(7, −8) as endpoints of a diameter, determine the circle's equation.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Solution · 4 marks
- 1Centre = midpoint of AB = ((−3 + 7)/2, (6 − 8)/2) = (2, −1)
- 2r² = (−3 − 2)² + (6 − (−1))² = 25 + 49 = 74
- 3(x − 2)² + (y + 1)² = 74
Answer(x − 2)² + (y + 1)² = 74 or x² + y² − 4x + 2y − 69 = 0
Stuck on a step? Read the free lesson: The Equation of a Circle
Practise more the equation of a circle questions
Real 0606 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on the equation of a circle
Also searched as: 0606/12/F/M/25 · 0606_m25_qp_12 · 0606 m25 12 · question 3.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.