0606/11 Oct/Nov 2025, Question 3: Solving Exponential and Log Equations
Cambridge IGCSE Additional Mathematics 0606 · Paper 11 (Non-calculator) · Non-calculator · 9 marks
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The question, in short
Solve two equations: a logarithmic equation in base 2 and x, and an exponential equation involving e with x² terms.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 5 marks
Solve log₂ x − 4 = 5 log_x 2 for x.
- 1Change of base: log_x 2 = 1/log₂ x
- 2log₂ x − 4 = 5/log₂ x ⇒ (log₂ x)² − 4 log₂ x − 5 = 0
- 3(log₂ x − 5)(log₂ x + 1) = 0
- 4log₂ x = 5 or −1
- 5x = 2⁵ = 32 or x = 2⁻¹ = 1/2
Answerx = 32 or x = 1/2
Part (b) · 4 marks
Solve e^(x² − 3) = 25e^(7 − x²) for x.
- 1Divide: e^(x² − 3 − (7 − x²)) = 25
- 2e^(2x² − 10) = 25
- 32x² − 10 = ln 25
- 4x² = (ln 25 + 10)/2 = 5 + ln 5
- 5x = ±√(5 + ln 5)
Answerx = ±√(5 + ln 5)
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Also searched as: 0606/11/O/N/25 · 0606_w25_qp_11 · 0606 w25 11 · question 3.
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