4024/23 May/Jun 2026, Question 18: Upper and Lower Bounds
Cambridge O Level Mathematics 4024 · Paper 23 (Calculator) · Calculator · 4 marks
اقرأ هذا الحل مشروحاً بالعربي ←
The question, in short
A rectangle has width w stated as 7 cm to the nearest centimetre and area 161.8 cm² to the nearest 0.1 cm². Find the range of w and the greatest possible length.
Summarised in our own words. Use the official paper for the exact wording and any diagrams.
Part (a) · 2 marks
Fill in the two missing values in the inequality showing all possible values of w, given 7 cm rounded to the nearest centimetre.
- 1Half of 1 cm is 0.5 cm
- 2Lower bound 7 − 0.5 = 6.5, upper bound 7 + 0.5 = 7.5
Answer6.5 ≤ w < 7.5
Part (b) · 2 marks
Using the area rounded to the nearest 0.1 cm², work out the largest possible value of the rectangle's length.
- 1Upper bound of area = 161.85
- 2Lower bound of width = 6.5
- 3Upper bound of length = 161.85 ÷ 6.5 = 24.9 cm
Answer24.9
Stuck on a step? Read the free lesson: Upper and Lower Bounds
Practise more upper and lower bounds questions
Real 4024 past-paper questions, marked on your working like the exam, with a worked solution for every part.
Practise free on LemmaraMore past-paper questions on upper and lower bounds
Also searched as: 4024/23/M/J/26 · 4024_s26_qp_23 · 4024 s26 23 · question 18.
Lemmara is an independent study tool, not affiliated with or endorsed by Cambridge International Education. The worked solutions are Lemmara’s own.