4024/12 Oct/Nov 2020, Question 18: Speed, Distance and Time
Cambridge O Level Mathematics 4024 · Paper 12 (Non-calculator) · Non-calculator · 5 marks
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The question, in short
Using Safira's distance–time graph from home to a shop and back between 08 15 and 08 50, find her stop time, her brother's journey graph and meeting distance, and her walking speed in km/h.
Summarised in our own words. Use the official paper for the exact wording and the diagram.
Part (a) · 1 mark
Find how many minutes Safira spends stationary at the shop.
- 1The graph is horizontal from 08 30 to 08 35
- 2Time in shop = 5 minutes
Answer5
Part (bi) · 1 mark
Draw the graph of her brother's walk to the shop, leaving at 08 30 at Safira's speed.
- 1Safira takes 15 minutes to walk 1200 m, so the brother does too
- 2Draw a straight line from (08 30, 0) to (08 45, 1200)
Answerline from (08 30, 0) to (08 45, 1200)
Part (bii) · 1 mark
Find how far her brother is from the shop when he meets Safira.
- 1The lines cross at 08 40, at 800 m from home
- 2Distance from shop = 1200 − 800 = 400 m
Answer400
Part (c) · 2 marks
Calculate Safira's walking speed to the shop in km/h.
- 1Distance = 1200 m = 1.2 km, time = 15 min = 1/4 hour
- 2Speed = 1.2 ÷ 1/4 = 4.8 km/h
Answer4.8 or 4 4/5 or 24/5
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Also searched as: 4024/12/O/N/20 · 4024_w20_qp_12 · 4024 w20 12 · question 18.
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